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kari74 [83]
1 year ago
11

Heather worked her to regular hours last week plus 10 overtime hours at the time and a half rate her gross pay was $652 What was

her hourly rate?
Mathematics
1 answer:
Tema [17]1 year ago
5 0

Consider that x is the payment per hour Heather earns. If she workes her 40 regular hours plus 10 overtime hours payed as an hour and half, then, you can write algebraicaly:

40x + 10(x + 0.5x) = 652

It is necessary to solve the previous equation for x, just as follow:

40x + 10(x + 0.5x) = 652 simplify inside parenthesis

40x + 10(1.5x) = 652

40x + 15x = 652 simplify like terms left side

55x = 652 divide both sides by 55

x = 11.85

Hence, the rate per hour is $11.85

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For his long distance phone service, Keith pays an $8 monthly fee plus 6 cents per minute. Last month, Keith's long distance bil
butalik [34]

Answer:

my answer is 19.90

Step-by-step explanation: so what i did to get this answer is by adding all the numbers so i stack it in order of greater number to least numbers so i did 19.76 + $8 + 6 ( you don't have to put the dollar sign when you add the numbers) and after i added those i got 19.90 as my answer.

hope it helps you

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4 years ago
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Lemur [1.5K]

No wonder !

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3 0
3 years ago
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use
evablogger [386]

Answer:

(1)  Null Hypothesis, H_0 : \mu_1 = \mu_2

    Alternate Hypothesis, H_1 : \mu_1\neq \mu_2

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let \mu_1 = mean annual family income for 12 people making inquiries at the first development

\mu_2 = mean annual family income for 24 people making inquiries at the second development

s_1 = standard deviation of annual family income for 12 people making inquiries at the first development

s_2 = standard deviation of annual family income for 24 people making inquiries at the second development

n_1 = sample of people of first development i.e. 12

n_2 = sample of people of second development i.e. 24

(1) Null Hypothesis, H_0 : \mu_1 = \mu_2  {population means are same}

  Alternate Hypothesis, H_1 : \mu_1\neq \mu_2  {population means are different}

<u>DECISION RULE ;</u>

  • If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, H_0 .
  • If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, H_0 .

(2) The test statistics is given by;

                      \frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where,  X_1bar = Sample mean income of people at first development

                        = $153,000

X_2bar = Sample mean income of people at second development = $171,000  

s_1 = $42,000  and   s_2 = $30,000

   s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2}} =  \sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2}  }{12+24-2}} = 34344.30

Test statistics = \frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24}  } } ~ t_3_4

                       = -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

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