Answer:
There is nothing here to answer
Step-by-step explanation:
Answer:
450
Step-by-step explanation:
Answer:
Whenever you assume values, try and make them as accurate as possible i.e. I am looking for consecutive even numbers so I will assume the values to be (2n - 2), 2n and (2n + 2)
s2−r2−q2=(2n+2)2−(2n)2−(2n−2)2s2−r2−q2=(2n+2)2−(2n)2−(2n−2)2
You get: 4n (4 - n)
So the solution must have 4 as a factor, which we see all options do.
To get -20, n(4-n) must be (-5). It will happen when n = 5.
To get 0, n = 0
To get 12, n(4-n) must be 3. It will happen when n = 3
To get 16, n(4-n) must be 4. It will happen when n = 2
There is no way n(4-n) could be 2 if n is an integer so 8 is not possible.Step-by-step explanation:
When we sort the terms in descending order, we get 3x^6 - 4x^3 + 8x + 9
The exponents decrease (from 6 to 3 to 1 to 0) with the largest exponent term on the left side and the smallest on the right side.
Fill in the missing terms to get 3x^6 + 0x^5 + 0x^4 + (-4x^3) + 0x^2 + 8x^1 + 9x^0
So the sequence of coefficients are 3, 0, 0, -4, 0, 8, 9
The answer to your question is 28%
:)
