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anzhelika [568]
3 years ago
14

Find the area of the triangle having vertices p(1, 3), q(−1, 1), r(−3, 2).

Mathematics
1 answer:
dlinn [17]3 years ago
7 0
See, pls, the offered decision, which consists of 2 ways: way1 based on vectors, way2 based on planimetry.

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I need help with this question for today please help me I really need help in this
igor_vitrenko [27]

Answer:

The answer is the second answer choice

Step-by-step explanation:

3 0
3 years ago
Find the x -intercept and the y -intercept. Then use them to graph the line of 6x+2y=-12
Neko [114]
The x intercept is when y=0
6x+0=-12
x=-2, now you have point A with coordinates (-2, 0)
The y intercept is when x=0
0+2y=-12
y=-6, so you have another point with coordinates (0, -6)
Connect those two points, you have your graph. It is a line.

8 0
3 years ago
Find the first three output values of the fractal generating function . –3 + 2i, –34 – 129i, 8354 + 7526i –3 + 2i, 2 – 10i, 8354
Dimas [21]

Fractal Generating Function, is

 f(z)=z²-3+2i

⇒f(0)=0²-3+2i

f(0)= -3+2i

⇒f(-3+2i)

  =(-3+2i)²-3+2i

 =9-4-12 i-3+2i

=2-10 i

⇒f(2-10i)

 =(2-10i)²-3+2i

 =4-100-40i-3+2i

 = -38 i-99

So, First three output values of the fractal generating function are

1.⇒ -3+2i

2. ⇒ 2-10 i

3.⇒-38 i -99

8 0
3 years ago
I need help solving it
Tom [10]
The number of cubes is 27
the volume is 36 centimeters cubed
4 0
3 years ago
Read 2 more answers
-10-2v&lt;6 and 6v+12&lt;-6. <br>need some help with this problem i keep messing a step
Galina-37 [17]
-10 - 2v < 6                   6v + 12 < -6
-2v < 6 + 10                  6v < -6 - 12
-2v < 16                        6v < -18
v > -16/2                       v < -18/6
v > -8                            v < -3

solution is : -8 < v < -3
7 0
3 years ago
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