Answer is 4 so C for you. I just did this with my brother! Hope this helped.
*the figure is shown in the attachment
Answer/Step-by-step explanation:
Since <XYZ and <YZX are said to be congruent, therefore, the side opposite to each of the angle are also equal. Therefore, ∆XYZ is an isosceles ∆.
Find the value of n by creating an equation to solve for n:
XY = (9n + 12) ft
XZ = (15n - 6) ft
XY = XZ (2 equal lengths of isosceles ∆)
9n + 12 = 15n - 6 (substitution)
Combine like terms
9n - 15n = - 12 - 6
-6n = -18
Divide both sides by -6
-6n/-6 = -18/-6
n = 3
Find the length of leg XY by substituting n = 3 into XY = (9n + 12) ft.
XY = (9(3) + 12) ft
XY = (27 + 12) ft
XY = 39 ft
Find the length of leg XZ by substituting n = 3 into XZ = (15n - 6) ft.
XZ = (15(3) - 6) ft
XZ = (45 - 6) ft
XZ = 39 ft
Answer: Y=5
Step-by-step explanation:
Your line has no slope. It is a horizontal line
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
Answer:
7^9
Step-by-step explanation:
When dealing with exponents inside and outside parenthesis with only one term in the parenthesis, you multiply the exponents. By doing this, you get 7^3x3, which is 7^9
