2 years ago

Find the x -intercept and the y -intercept. Then use them to graph the line of 6x+2y=-12

1 answer:

8 0

The x intercept is when y=0
6x+0=-12
x=-2, now you have point A with coordinates (-2, 0)
The y intercept is when x=0
0+2y=-12
y=-6, so you have another point with coordinates (0, -6)
Connect those two points, you have your graph. It is a line.

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Solve the quadratic equation x2+8x−30=0 by completing the square.

diamong [38]

Answer:

$\bold{x=-4\pm\sqrt{46}}$

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\\\\\\x^2+8x-30=0\\\\\underbrace{x^2+2\cdot x\cdot 4+4^2}-4^2-30=0\\\\{}\qquad(x+4)^2\,-\,16-30=0\\\\{}\qquad\ \ (x+4)^2=46\\\\ {}\qquad\ \ x+4=\pm\sqrt{46}\\\\ {}\qquad\ \ x=-4\pm\sqrt{46}$