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DochEvi [55]
2 years ago
8

How many real solutions does the system have ? y = - 3x - 1; y = x ^ 2 - 3x + 4

Mathematics
1 answer:
kirill115 [55]2 years ago
7 0

The only solution the system of the equation has is x = -1/3.

The number of solutions is one.

<h3>What is an equation?</h3>

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

The system of equations:

y = -3x - 1

y = x² - 3x + 4

The solutions of the equation.

y = 0

So,

-3x - 1 = 0

-3x = 1

x = -1/3

x² - 3x + 4 = 0

It is in the form of ax² + bx + c = 0

a = 1, b = -3, and c = 4

Now,

x = -b ± √(b² - 4ac) / 4a

x = 3 ± √(9 - 16) / 4

x = 3 ±√-7 / 4

x = 3 ±i√7 / 4

This is a complex root.

So,

These are not real solutions.

Thus,

The only solution the system of the equation has is x = -1/3.

The number of solutions is one.

Learn more about equations here:

brainly.com/question/17194269

#SPJ1

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