All categories

1 year ago

Help pls!!! I WILL BRAINIEST!!!!

Mathematics

1 answer:

slavikrds [6]1 year ago

4 0

The maximum the company can expect for returned items is $4190.

<h3>What is the percentage?</h3>

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, The average daily profit of an electronics store is $27,235.

The company estimates that 15% is lost each day to returns.

∴ The amount of return is (15/100)×27135.

= 0.15×27125.

= $4068.

Now this has an error of ± 3%, therefore the maximum the company can expect for returned items is {(100 + 3)/100}×100

= 1.03×4068.

= $4190.

Learn more about percentages here :

brainly.com/question/24159063

#SPJ1

You might be interested in

F(x) = x + 2<br> g(x) = x - 4<br> (f9)(x) =

san4es73 [151]

Answer:

(fºg)(x) = x -2

Step-by-step explanation:

f(x) = x + 2

g(x) = x - 4

(fºg)(x) = ( x - 4) + 2

(fºg)(x) = x -2

3 0

3 years ago

The manager of a store marks up all items by 15%. If x is the original price, what is the new price with the mark up?

Crank

Answer:

x + 0.15x = OP

Step-by-step explanation:

OP= Original Price

3 0

3 years ago

Assappp<br> Please Help me

Karolina [17]

Answer:

use photomath!

Step-by-step explanation:

3 0

3 years ago

Evaluate. -3 -4 4 undefined

aev [14]

The algebra question should look like this: <u><em>3^√-64</em></u>.

The answer is -4.

8 0

3 years ago

In Sweden, 10 people are struck by lightning every year, on average. Answer thefollowing questions about a given year in Sweden

emmainna [20.7K]

Answer:

a) 19.85% probability that a total of two people are struck by lightning during first four months of the year.

b) 22.68% probability that the year has 5 good and 7 bad months

Step-by-step explanation:

We are going to use the Poisson distribution and the binomial distribition to solve this question.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a.Find the probability that a total of two people are struck by lightning during first four months of the year.

10 people during a year(12 months).

In 4 months, the mean is $\mu = \frac{10*4}{12} = 3.33$

This is P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-3.33}*(3.33)^{2}}{(2)!} = 0.1985$

19.85% probability that a total of two people are struck by lightning during first four months of the year.

b.Say that a month is good is no one is struck by lightning, and bad otherwise. Find the probability that the year has 5 good and 7 bad months.

Probability that a month is good.

P(X = 0), Poisson

The mean is $\mu = \frac{10*1}{12} = 0.8333$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8333}*(0.8333)^{0}}{(0)!} = 0.4346$

Find the probability that the year has 5 good and 7 bad months.

Now we use the binomial distribution, we want P(X = 5) when n = 12, p = 0.4346. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{12,5}.(0.4346)^{5}.(0.5654)^{7} = 0.2268$

22.68% probability that the year has 5 good and 7 bad months

3 0

3 years ago