The chord length is the same as the radius, so R^2 = 9.
Area = (1/2)(9)(pi/3 - sqrt(3)/2) = (3/4) (2 pi - 3 sqrt(3))
Answer:
D. 68%
Step-by-step explanation:
The following statistics are given;
sample mean = 47%
s = 5% ; the sample standard deviation
n = 625 ; the sample size
The confidence interval for a population mean is given as;
sample mean ± z-score*
Substituting the above values we have;
47 ± z-score*
47 ± z-score*0.2
The confidence interval has been given as;
lower limit = 46.8%
upper limit = 47.2%
We can use any of these two values with the above expression to solve for the z-score. Using the lower limit we have the following equation;
47 - z-score*0.2 = 46.8
-z-score*0.2 = 46.8 - 47
-z-score*0.2 = -0.2
z-score = 1
The area of the standard normal curve between -1 and +1 will be the confidence level for the given confidence interval.
Pr( -1<Z<1 ) = 0.68 = 68%
From the Empirical rule
I think she picked 12 more daisies than tulips
Answer:
d. x = 5
Step-by-step explanation:
Chords that subtend congruent arcs are congruent.
<h3>Setup</h3>
Chord lengths are the same:
AB = CD
16x -2 = 14x +8
<h3>Solution</h3>
2x = 10 . . . . . . add 2-14x
x = 5 . . . . . . . . divide by 2
Answer:
Dimension of the enclosure is 56.56 ft * 14.14 ft
Step-by-step explanation:
Given -
Let us suppose that x is the length of steel fence and y is the length of one side of pine boards
We know that - xy = 800.
y = 800/x
Let us say that C is the cost of fence
= 3x + 6(2y) = 3x + 12y = 3x + 12(800/x)
C = 3x + 9600x-1, x > 0
C' = 3 - 9600x-2 = (3x2-9600)/x2
C' = 0 when 3x2 = 9600
x2 = 3200
x = √3200 ft ≈ 56.56 ft
So, the cost is minimized when x ≈ 56.56 ft and y = 800/x ≈ 14.14 ft