A 15 foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece
1 answer:
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Answer:
407 mi/h
Step-by-step explanation:
Given:
Speed of plane (s) = 470 mi/h
Height of plane above radar station (h) = 1 mi
Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.
Consider a right angled triangle representing the above scenario.
We can see that, the height 'h' remains fixed as the plane is flying horizontally.
Speed of the plane is nothing but the rate of change of horizontal distance of plane. So,
Now, applying Pythagoras theorem to the triangle, we have:
Differentiating with respect to time 't', we get:
Now, when the plane is 2 miles away from radar station, then D = 2 mi
Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,
Now, plug in all the given values and solve for . This gives,
Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.
Answer:
(a) and (b) are correct
Step-by-step explanation:
Given
See attachment for complete question
Required
Select the correct options
A clock is divided into two equal parts.
(1) 1 - 6
(2) 7 - 12
<em>When the hour hand is on (1), then the time is "after"</em>
<em>When the hour hand is on (2), then the time is "before"</em>
<em />
From the attached clock, we have:
(1) The hour hand on 9
(2) The minute hand 1 unit above 9 i.e. 46 minutes
(1) implies that, the time is before 9 i.e. past 8
(2) implies that the minutes is (60 - 46) before 9 or 46 minutes after 8
In (1) and (2) above, we have two interpretations.
1: (60 - 46) minutes before 9
This gives:
14 minutes before 9
2: 46 minutes past 8
i.e. 8 : 46
