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ycow [4]
11 months ago
11

Y=−2x+4y, equals, minus, 2, x, plus, 4

Mathematics
1 answer:
vlabodo [156]11 months ago
3 0

The missing value of the solution to the equation y = −2x + 4, is: 3.

<h3>What is the Solution to an Equation?</h3>

The solution to a given equation, is the x and y values of an ordered pair that would make the equation true, if we substitute their values into the equation.

Given the equation, y = -2x + 4, and we have (x, -2) as the solution where the value of x is the missing value in the solution, to find the value of x, substitute y = -2 into the equation and solve for x:

-2 = -2x + 4

Subtract 4 from both sides

-2 - 4 = -2x + 4 - 4 (subtraction property of equality)

-6 = -2x

Divide both sides by -2

-6/-2 = -2x/-2

3 = x

x = 3

Therefore, the missing value is: 3.

Learn more about the solution to an equation on:

brainly.com/question/25678139

#SPJ1

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Find the upper 20%of the weight?
meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

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2 years ago
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