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3 years ago

ok so i put a 5 it the last one and it was right but i dunno the rest cause the 4 that i put in aint right. 20 points

Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Step-by-step explanation:

1. 3:1

2. 12:4

3. 15 : 3

plz mark my answer as brainlist and plzzzz vote me also . hope this will help you

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Rachna purchases a plant that is 6 inches tall. Every week the plant grows an additional 0.6 inches. Rachna draws a graph of the

aleksklad [387]

Answer:

0.6

Step-by-step explanation:

Slope is the change in y divided by change in x.

x is weeks

y is height

We know plant grows 0.6 inches every week. This means per 1 week [change in x], the plant grows 0.6 inches [change in y]

Slope = 0.6/1 = 0.6

0.6 is the slope of the function

5 0

3 years ago

8(1/2u+3/4)

netineya [11]

Answer:

4u+3

Step-by-step explanation: 8/1*1/2= 8/2=4u

8/1*3/4= 24/8=3

4 0

3 years ago

The point (-6, 4) is reflected over the x-axis.<br> What is the new point?

defon

Answer:

p (6, -4)-------------->p'(6,4)

7 0

3 years ago

Consider the quadratic equation x2 + 2x - 35 = 0. Solve by factoring and using the zero-product property.

Morgarella [4.7K]

Answer:

x = -7

x = 5

Step-by-step explanation:

The standard form of quadratic equations is

Ax^2 + Bx + C = 0

The factors need to multiply together to be C and add together to be B.

The two numbers that will multiply together to be -35 and add together to be 2 are -5 & 7.

The factor pairs are (x+7)(x-5). Zero product property means we set each of those factor pairs = 0 and solve.

x + 7 = 0

-7 -7 Subtract 7 from each side to solve

x = -7

x - 5 = 0

+5 +5 Add 5 to each side to solve

x = 5

4 0

2 years ago

Read 2 more answers

A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

IgorC [24]

Answer

According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

$T(0) = Ce^{0} + T_a$

10 = C + 100

C = -90

now,

$12 = -90e^k + 100$

$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$70 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{3}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})$

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{45}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})$

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

5 0

3 years ago