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jonny [76]
1 year ago
9

You're asked to recommend potential data structures to use as the backing for implementing Kruskal's algorithm. Which of the fol

lowing data structures would be most runtime-efficient? If there are multiple best options, select all of them. Linked List Hash Table Heap AVL Tree Red-Black Tree Huffman Tree None of the above Submitted
Computers and Technology
1 answer:
Sliva [168]1 year ago
7 0

Although Kruskal's algorithm creates numerous trees that eventually connect to form a single final solution, it always ensures minimality.

One of the major problems facing civil engineers at the beginning of the 20th century was the difficulty of electrifying towns and cities. Otakar Borvka, a Moravian professor, thought about the issue and developed a solution in 1926.

More impressively, Borvka presented the solution as an abstract weighted graph rather than just in terms of wires and electricity. The absence of backup connections necessitates the use of a tree as a solution (as opposed to a graph, which may contain multiple paths or cycles), the connectedness requirement necessitates the use of a spanning tree (as opposed to a disconnected forest of multiple trees), and the cost focus necessitates the use of a minimum spanning tree.

To know more about necessitates click here:

brainly.com/question/15110451

#SPJ4

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Answer: it indents

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The subscription service that complements App-ID by enabling you to configure the firewall to identify and control access to websites is  URL Filtering.

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4 0
3 years ago
Write the Python code to implement each step of the following algorithm. Your code should use descriptive variable names and per
Lina20 [59]

Answer:

# the number of pizza is initialised

# to 5

number_of_pizza = 5

# number of slice in each pizza

# is initialised to 8

slice_in_each_pizza = 8

# total number of pizza is calculated

total_number_of_slices = number_of_pizza * slice_in_each_pizza

# number of guest who respond yes

# is initialised to 10

number_of_guest_respond_yes = 10

# additional 3 guest is added to existing guest

number_of_guest_respond_yes += 3

# number of left over slice is gotten by using modulo arithmetic

number_of_left_over_slice = total_number_of_slices % number_of_guest_respond_yes

# the number of left over slice

# is printed which is 1

print(number_of_left_over_slice)

Explanation:

Missing Question Part: Use a variable to store the number of pizzas ordered as 5.

Assuming there are 8 slices in each pizza, use a variable to store the total number of slices calculated using the number of pizzas ordered.

Use another variable to store the number of guests who had responded YES as 10.

Three more people responded YES. Update the corresponding variable using an appropriate expression.

Based on the guest count, set up an expression to determine the number of left-over slices if the slices would be evenly distributed among the guests. Store the result of the expression in a variable.

The program is written in Python and it is well commented.

6 0
3 years ago
In most programming languages, the compiler carries a preprocessing step to determine if certain statements will compile. For in
MakcuM [25]

Answer:

See explaination for program code

Explanation:

package com.company;

import java.io.IOException;

import java.nio.file.Files;

import java.nio.file.Paths;

import java.util.Stack;

/*

* A program which reads input from given text filename and prints

* whether it passed the pre-processing stage or not

* Sample input

* int A = (a + b);static void display(int x)

* {

* //A sample input file

* }

* */

public class MyPreprocessor {

/*

* Reads input from filename and returns a string

* containing whole text

* */

public String readInput(String filename) {

String content = "";

try {

content = new String(Files.readAllBytes(Paths.get(filename)));

} catch (IOException e) {

e.printStackTrace();

}

return content;

}

/**

* Filters input since we are only concerned with

* a subset of input = '{}[]()/*'

*/

public String filterText(String text) {

String output = "";

for(int i = 0;i<text.length();++i) {

switch (text.charAt(i)) {

case '[':

case ']':

case '{':

case '}':

case '(':

case ')':

case '*':

case '/':

output += text.charAt(i);

}

}

return output;

}

/*

* Uses stack to determine if input is valid or not

* */

public boolean parse(String input) {

Stack<Character> St = new Stack<Character>();

// '$' is special symbol to represent bottom of stack

St.push('$');

for(int i = 0;i<input.length();++i) {

Character symbol = input.charAt(i);

if(St.peek().equals(getOpenSymbol(symbol)))

St.pop();

else St.push(symbol);

}

return St.peek() == '$';

}

private static Character getOpenSymbol(Character symbol) {

switch (symbol) {

case '}': return '{';

case ']': return '[';

case ')': return '(';

case '*': return '*';

case '/': return '/';

default: return ' ';

}

}

public static void main(String[] args) {

MyPreprocessor preprocessor = new MyPreprocessor();

String inputText = preprocessor.readInput("src/input.txt");

String filteredInput = preprocessor.filterText(inputText);

if(preprocessor.parse(filteredInput))

System.out.println("preprocessing passed.");

else System.out.println("preprocessing failed!");

}

}

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4 years ago
Why would it be unusual to find a fossil of an organism’s eye?
Slav-nsk [51]
<span>The preservation of anything other than mineral skeletons is (with a few exceptions described below) an extremely rare event. Anything that can decay is likely to be lost. Fur, skin, internal organs – all are immensely vulnerable to the destruction by bacteria, fungi and scavengers that assure their recycling back into the ecosystem. </span>
8 0
3 years ago
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