Answer:
Yes. Pseudocode is an improvement over the IPO chart because it lays out the sequence of steps for a particular program
Explanation:
The input–process–output (IPO) chart is a widely used approach in systems analysis and software engineering for describing the structure of an information processing program or other process. The chart has three components (Input, Process and Output), and you write the description of each component in plain English, not code or mathematical formulas.
Pseudocode is a procedure for solving a problem in terms of the actions to be executed and the order in which those actions are to be executed.
Pseudocode is an improvement over the IPO chart because it shows the step by step sequence to be followed by a particular program unlike the IPO chart which just break the program into Input, Process and Output.
Using the knowledge of pseudocodes it will be possible to write a code that calculates the amount of hours worked and giving warnings about it.
<h3>Writing a pseudocode we have that:</h3>
<em>while </em>
<em>if number == 0</em>
<em>break</em>
<em>hours =0 </em>
<em>for i =1 to 5 </em>
<em>hours = hours + time_out[ i ] - time_in[ i ]</em>
<em> If hours >36 : </em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Congratulaion! Your working hours are more than 36")</em>
<em>If hours <30 : #</em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Warning !!!")</em>
<em>End loop</em>
See more about pseudocode at brainly.com/question/13208346
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The answer would be a C class fire extinguisher.
So here is the code in Python:
n = 0.00 #this is a float because there are some numbers that are decimals.
while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.
You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.
