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True [87]
1 year ago
9

A rectangular garden is 15 feet wide. If its area is 1050ft², what is the length of the garden?

Mathematics
1 answer:
joja [24]1 year ago
6 0

The width is w=15 ft.

The area is A=1050 sq ft.

The length of the garden is,

\begin{gathered} L=\frac{A}{w} \\ =\frac{1050ft^2}{15ft} \\ =70ft \end{gathered}

Thus, the length of the garden is 70 ft.

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The equation that represents the motion of the string is given by:

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Substitute the given values in [1] we get;

y =0.6e^{-1.8t}\cos(2\pi 105t)  

or

y =0.6e^{-1.8t}\cos(210\pi t)  

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The trigonometric function that models the motion of the string is given by:

y =0.6e^{-1.8t}\cos(210\pi t)

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Determine the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24

Using graphing calculator for the equation

y =0.6e^{-1.8x}\cos(210\pi x)

let x = t (time in sec)  

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24 is, 0.5 sec


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