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Afina-wow [57]
3 years ago
12

Cos (a + 60 ) + Cos (a-60)​

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

the answer is 0.9988747935

hope that works!!

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What is the answer for 34-54x
Brums [2.3K]

Answer:

2(17-27x)

Step-by-step explanation:

Since the question was incomplete this is the only answer I have for you.

If you were looking for the answer of X I would need a answer for the equation

Anyways... you want to factor out 2 from the expression since there are two numbers

Once you factored out the two (divide each number by 2) you'll get:

2(17-27x)

5 0
3 years ago
Read 2 more answers
Find an equation of a line passing through the point (8,9) and parallel to the line joining the points (2,7) and (1,5).
TiliK225 [7]

Answer:

2x - y - 7 = 0

Step-by-step explanation:

Since the slope of parallel line are same.

So, we can easily use formula,

y - y₁ = m ( x ₋ x₁)

where, (x₁, y₁) = (8, 9)

and m is a slope of line passing through (x₁, y₁).

and since the slope of parallel lines are same, so here we use slope of parallel line for calculation.

and, Slope = m = \dfrac{y_{b}-y_{a}}{x_{b}-x_{a}}

here, (xₐ, yₐ) = (2, 7)

and, (y_{a},y_{b}) = (1, 5 )

⇒ m = \dfrac{5-7}{1-2}

⇒ m = 2

Putting all values above formula. We get,

y - 9 = 2 ( x ₋ 8)

⇒ y - 9 = 2x - 16

⇒ 2x - y - 7 = 0

which is required equation.

3 0
3 years ago
Read 2 more answers
How do I do this? We did a smaller one but I don’t know how to do this.
ivolga24 [154]

Answer:

Step-by-step explanation:

3 0
3 years ago
Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de
Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=7\\\\H_a:\mu> 7

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25

The degrees of freedom for this sample size are:

df=n-1=49-1=48

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>5.25)=0.000002

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0
3 years ago
PLZ I NEED THIS ASAP!! ILL GIVE YOU BRAINLIST!!!
irinina [24]

Answer:

Yes

Step-by-step explanation:

y = 5x

7 0
3 years ago
Read 2 more answers
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