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soldier1979 [14.2K]
3 years ago
9

What type of graph is best to compare two sets of data over time

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
D. double line graph.
Vitek1552 [10]3 years ago
3 0

The correct answer is D..........

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Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). Tiles f(x) = x2 − 9, and
vitfil [10]
For this case we must solve each of the functions.
 We have then:

 f (x) = x2 - 9, and g (x) = x - 3
 h (x) = (x2 - 9) / (x - 3)
 h (x) = ((x-3) (x + 3)) / (x - 3)
 h (x) = x + 3

 
f (x) = x2 - 4x + 3, and g (x) = x - 3
 
h (x) = (x2 - 4x + 3) / (x - 3)
 h (x) = ((x-3) (x-1)) / (x - 3)
 h (x) = x-1

 f (x) = x2 + 4x - 5, and g (x) = x - 1
 h (x) = (x2 + 4x - 5) / (x - 1)
 h (x) = ((x + 5) (x-1)) / (x - 1)
 h (x) = x + 5

 f (x) = x2 - 16, and g (x) = x - 4
 h (x) = (x2 - 16) / (x - 4)
 h (x) = ((x-4) (x + 4)) / (x - 4)
 h (x) = x + 4
4 0
3 years ago
Read 2 more answers
Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch
Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30  (3).

Writing equations (1) and (3) in matrix form, we have

\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]

Using Cramer's rule to solve for x and y,

x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

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3 years ago
You have 3434 of a pie leftover after your party. Each guest takes home 1616 of the leftover pie.
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You would have 1818 of pie left over...... I do not know the fraction of it
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The answer is $14 Saul put into his bank accout
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