Answer:
false but Least common multiple (LCM) of 6 and 12 is 12.
For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value =
= 5.29
Answer:
1766.3
Step-by-step explanation:
V=4
/3πr^3
= 4/3(3.14)(7.5)^3
= 4/3(3.14)(421.88)
= 4/3(1324.69)
= 1766.25
= 1766.3
I hope this is right!
Answer:
The answer is x=20
Step-by-step explanation:
27-7=20
x=20