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3 years ago

I don't understand this at all plz just help no explanation needed

Mathematics

1 answer:

Finger [1]3 years ago

4 0

Answer: 24

Step-by-step explanation:

i solved it and can give explanation if needed :)

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Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

3 0

3 years ago

Y=-3x+2, find the y-values for <br> (0,?)<br> (-1,?)<br> (1,?)<br> (1/3,?)

s2008m [1.1K]

y = -3x + 2

1) x = 0

y = (-3)*0 + 2

y = 2

(0,2)

2) x = -1

y = (-3)*(-1) + 2

y = 5

(-1,5)

3) x = 1

y = (-3)*1 + 2

y = -1

(1,-1)

4) x = 1/3

y = (-3)*(1/3) + 2

y = 1

(1/3,1)

8 0

3 years ago

Read 2 more answers

Question 1 of 10 10 Points AB¯¯¯¯¯¯¯¯ is the diameter of circle T. Point A is located at (-4,2) and point B is located at (2,-8)

wariber [46]

Answer:

The coordinates of the center of this circle is (-1, -3).

Step-by-step explanation:

As we know that $A = (-4,2)$ and $B = (2,-8)$ are points lying on circle T, the center is the midpoint of the segment AB, whose location can be obtained from Midpoint formula: