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Gnoma [55]
1 year ago
10

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

simplest form.

Mathematics
1 answer:
umka2103 [35]1 year ago
7 0

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

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x is less than or equal to 2
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5 0
3 years ago
Find Y <br>.............. ​
N76 [4]

Answer:

y = 40 / sqrt(pi)

Step-by-step explanation:

The area is 400

We want to find the diameter

400 = pi r^2

Divide each side by pi

400/ pi = r^2

Take the square root of each side

sqrt(400/ pi) = sqrt(r^2)

20/ sqrt(pi) = r

The diameter is twice the radius

2 r = d

2 * 20/ sqrt(pi) = d

40 / sqrt(pi) =d

y is the diameter so

y = 40 / sqrt(pi)

4 0
3 years ago
Can anyone help me with this problem ?
Elena L [17]
Come now !  I'm sure you could unravel it if you look at it and think about it
for a minute or two.

What's an angle bisector ?  It's a line that splits an angle exactly in half.
The two little angles on each side of it are EQUAL.  Each of them is exactly
half of the big angle.

So in this drawing,    (3/2 x - 6)    is equal to    (1/4 x + 4) .
Do you think you could find 'x' ?

3/2 x - 6  =  1/4 x + 4

Add 6 to each side of the equation:    3/2 x = 1/4 x + 10

Multiply each side by 4 :                     6 x = x + 40

Subtract 'x' from each side:                  5 x = 40

Divide each side by 5 :                          x = 8

Angle  CBD  is  1/4 x + 4 .  That's  1/4 (8) + 4 = 2 + 4 = <u>6 degrees </u>



3 0
3 years ago
Help with this question, ASAP!!
Taya2010 [7]

Answer:

The answer to your question is: second option

Step-by-step explanation:

g(x) = x + 4

- This function is linear because the power of x is 1, if the power were a different number it would not be linear.

- As the sign of 4 is positive, it means that the function is translated 4 units up.

- A constant is when there is a number, for example +4 or -4, in this example the function also has a letter "X" so it is not a constant.

7 0
3 years ago
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
3 years ago
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