In simplest form it's 5/7
The shapes are being used instead of variables.
For problem 4; start with clue 2, then clue 3, then clue 4, and lastly do clue 4.
<u>Clue 2</u>
3 · square - 8 = 19
3 · square = 27 <em>added 8 to both sides</em>
square = 9 <em>divided both sides by 3</em>
<u>Clue 3</u>
2 · triangle + 3 = -3
2 · triangle = -6 <em>subtracted 3 from both sides</em>
triangle = -3 <em>divided both sides by 2</em>
<u>Clue 4</u>
square + triangle = 6
(9) + (-3) = 6 <em>substituted solutions from Clue 2 and Clue 3</em>
6 = 6 <em>True statement confirms that Clues 2 & 3 are correct</em>
<u>Clue 1</u>
star + square = 12
star + (9) = 12 <em>substituted solution from Clue 2 </em>
star = 3 <em>subtracted 9 from both sides</em>
Answer: triangle = -3, star = 3, square = 9
For problem 5; do the same thing as problem 4 and start with Clue 2
Answers: triangle = -2, star = 10, square = 8
Answer:
A=45
B=110
Step-by-step explanation:
Interior angles of a triangle add up to 180.
So, do 180-25=155.
Then, 155-65=90.
90 divided by 2 is 45.
x=45 so B is 45+65, which is 110.
Answer: -6, -3, -2, -1, 1, 2, 3, 6
<u>Step-by-step explanation:</u>
NOTES: p is the last term, q is the coefficient of the first term
Determine all of the factors of p and all of the factors of q
Possible rational roots are all of the combinations of p/q for every factor
![\dfrac{p}{q}=\pm \dfrac{6}{1}=\pm \dfrac{1\times 6, 2\times 3}{1}=\pm\dfrac{1}{1}, \pm\dfrac{6}{1}, \pm\dfrac{2}{1}, \pm\dfrac{3}{1}\\\\\\\text{In order from smallest to largest:}\ \large\boxed{-6, -3, -2, -1, +1, +2, +3, +6}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7Bq%7D%3D%5Cpm%20%5Cdfrac%7B6%7D%7B1%7D%3D%5Cpm%20%5Cdfrac%7B1%5Ctimes%206%2C%202%5Ctimes%203%7D%7B1%7D%3D%5Cpm%5Cdfrac%7B1%7D%7B1%7D%2C%20%5Cpm%5Cdfrac%7B6%7D%7B1%7D%2C%20%5Cpm%5Cdfrac%7B2%7D%7B1%7D%2C%20%5Cpm%5Cdfrac%7B3%7D%7B1%7D%5C%5C%5C%5C%5C%5C%5Ctext%7BIn%20order%20from%20smallest%20to%20largest%3A%7D%5C%20%5Clarge%5Cboxed%7B-6%2C%20-3%2C%20-2%2C%20-1%2C%20%2B1%2C%20%2B2%2C%20%2B3%2C%20%2B6%7D)