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Vladimir [108]
3 years ago
13

You need to measure the width of a window, but you do not have a ruler. You use a sheet of paper that is 8.5 inches wide. It fit

s across the window 3.5 times. About how wide is the window?
Mathematics
2 answers:
Stells [14]3 years ago
5 0
8.5*3.5=29.75 so yaaaaaaaaaaaaaaaaaaaaaaaaaaaa
swat323 years ago
3 0
8.5 × 3.5 = 29.75
Therefore, the window is approximately 29.75 inches wide.
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Tyler goes to the store. His budget is $125. Which inequality represents x, the amount in dollars Tyler can spend at the store?
raketka [301]

Answer:

The answer is A

Step-by-step explanation:

If Tyler's budget is $125, he cannot spend more than that. He can spend at most $125; which is represented as less than or equal to.

x \leqslant 125

6 0
3 years ago
Is (-5,-5) a solution of y \geq -2x +4y≥−2x+4 ?
FromTheMoon [43]

Answer:

  No

Step-by-step explanation:

Substitute the values and see.

  -5 ≥ -2(-5) +4

  -5 ≥ 14 . . . . . . . . FALSE

The point (-5, -5) is <em>not a solution</em> to the inequality

  y ≥ -2x +4

___

A graph can quickly show you this.

7 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
4 years ago
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6 0
3 years ago
Evaluate sin 5pi/4<br> Thank you
kondaur [170]

Answer:

3.92699081699

Step-by-step explanation:

\frac{5(3.14)}{4}\\=15.7/4

3 0
3 years ago
Read 2 more answers
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