I need to know the answer please…
1 answer:
Answer is a= 51/7 or 7 2/7
Step by step
-2/3 (a + 3) = 5/3a - 19
Distribute to resolve parentheses
-2/3a -2 = 5/3a - 19
Now to move variables to one side
Add 2/3a to both sides
-2/3a + 2/3a -2 = 5/3a + 2/3a -19
Combine like terms
-2 = 7/3a -19
Add 19 to both sides to isolate variable
-2 +19 = 7/3a -19 + 19
17 = 7/3a
Divide both sides by 7/3 to solve for a
(Remember when you divide a fraction, flip it and multiply.)
17 * 3/7 = a
51/7 = a
Picture attached shows steps in order, I think that is what you also needed?
Step by step
-2/3 (a + 3) = 5/3a - 19
Distribute to resolve parentheses
-2/3a -2 = 5/3a - 19
Now to move variables to one side
Add 2/3a to both sides
-2/3a + 2/3a -2 = 5/3a + 2/3a -19
Combine like terms
-2 = 7/3a -19
Add 19 to both sides to isolate variable
-2 +19 = 7/3a -19 + 19
17 = 7/3a
Divide both sides by 7/3 to solve for a
(Remember when you divide a fraction, flip it and multiply.)
17 * 3/7 = a
51/7 = a
Picture attached shows steps in order, I think that is what you also needed?
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Answer:
7 hours
Step-by-step explanation:
It is given that the plane was flying at 847 km/hour. So the speed of the plane was 847 kilometers per hour.
It is also given that the distance between Rome and New Delhi is 5,929 kilometers.
We know that the distance is equal to the product of speed and time, so we have,
, where 'd' represents the distance, 's' represents the speed, and 't' represents the time.
Putting the values we get,
Solving for 't' we get,
So the time taken to fly from Rome to New Delhi is 7 hours.
Given:
The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).
To find:
The area of the rectangle.
Solution:
Distance formula:
Using the distance formula, we get
Similarly,
Now, the length of the rectangle is and the width of the rectangle is
. So, the area of the rectangle is:
Therefore, the area of the rectangle is 20 square units.
Answer: C. (-4, -2)
<u>Step-by-step explanation:</u>
First, eliminate one of the variables and solve for the remaining variable:
2x - 5y = 2 → 3(2x - 5y = 2) → 6x - 15y = 6
3x + 2y = -16 → -2(3x + 2y = -16) → <u> -6x - 4y = 32</u>
-19y = 38
y = -2
Next, replace "y" with -2 into either of the original equations to solve for x:
2x - 5y = 2
2x - 5(-2) = 2
2x + 10 = 2
2x = -8
x = -4
x = -4, y = -2
<u>Check:</u>
Plug in the x- and y-values into the other original equation:
3x + 2y = -16
3(-4) + 2(-2) = -16
-12 + -4 = -16
-16 = -16