The sum of the interior angles of<span> a </span>triangle<span> are equal to 180</span>o<span>. To </span>find the third angle of a triangle<span> when the other two </span>angles<span> are known subtract the number of degrees in the other two </span>angles<span> from 180</span><span>o</span>
-2x+ 12 = x^2 +16
-2x -4 = x^2
-4= x^2 + 2x
-4= 3x
-4/3 = 3/3x
-1.333 (repeated) = x
That depends. If it is a fraction, can you cancel out some numbers? If it is an expression, can you combine like terms? Or do you need to factor?
Downstream DATA:
distance = 12 miles
time = 2 hours
rate = 12/2 = 6 mph
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Upstream DATA:
distance = 12 miles
time = 4 hrs
rate = 12/4 = 3 mph
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Equations:
Downstream: b + c = 6
Upstream::: b - c = 3
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Add to get:
2b = 9
b = 4.5 mph (speed of the boat in still water.)
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Solve for "c":
b + c = 6
4.5 + c = 6
c = 1.5 mph (speed of the current)
The answer is 1.5 mph