All categories

3 years ago

Simplify : i attatched an image

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

4 0

The answer is D. When you have an exponent in a log, you can take the exponent down:

5 * logBASE4(4)

When you have a log base to the same number as the base, it’s always 1.

5*1 is .

igor_vitrenko [27]3 years ago

3 0

For this case we have the following function:
(log4 (4 ^ 5))
Applying properties of logarithm we have:
loga (a ^ x) = x
Therefore, for this case we have:
(log4 (4 ^ 5)) = 5
Answer
The equivalent expression in this case is:
5
option D

You might be interested in

Given that the rectangle above has an area of 48 square units, find m angle klj. round the answer to the nearest hundreth.

slava [35]

Hello,

tan KLJ=6/8=3/4
=> mes angle KLJ=36.8698976558...°≈36.87 °
Answer B.

8 0

3 years ago

Read 2 more answers

!!HURRY IM BEING TIMED 40PTS!!

Rudik [331]

The average rate of change in a function from a to b is

$\frac{f(b)-f(a)}{b-a}$ .

For the left function, from x = 4 to x = 5, the rate of change is

$\frac{100-64}{5-4} = \frac{36}{1} = 36$ .

For the right function, the rate of change is

$\frac{1024-256}{5-4} = \frac{768}{1} = 768$

Using a ratio to compare the right function's growth rate with that of the left function, you get $768 \div 36 \approx 21.3$ .

The right function is growing approximately 21 times faster than the left function (over the interval from 4 to 5).

3 0

3 years ago

Read 2 more answers

Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

3 years ago

Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions

docker41 [41]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Grace wove a potholder with an area of 80 square inches. The lengths and widths of the sides are whole numbers. Which dimensions make the most sense for a potholder?

Since the Area of the potholder = 80 sq inch

And the dimension of the potholder ; length and width are integers ; Hence, possible dimensions could be ;

Area = length × width

80 = length × width

(80, 1), (40, 2), (20, 4), (10, 8), (16, 5)

Potholders are fabrics sewn from the purpose of being used to handle pots and other kitchen equipments.

Usually the dimension are usually close, hence, the most sensible dimension a potholder with an area of 80 sq inch could have is 8 by 10 or vice-versa.

7 0

3 years ago

Can someone please answer these 4 questions they don’t look hard- but I just need to understand please!! (If you can provide the

Nostrana [21]

Answer:

Thanks for the points

Step-by-step explanation:

6 0

3 years ago