Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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Answer : AB = 12
Explanation:
2x + 6 + 5x - 3 = 24
7x + 3 = 24
x = 3
AB = 2x + 6 = 2(3) + 6 = 12
Answer:
Rise=2 Run=1 type of slope is positive slope is 2 y int is 1 and the equation is y=2x+1
Step-by-step explanation:
1. First you need slope, slope is y1-x1/x2-y2 so then you get 4/2 which is 2, we also know rise/run so rise is 2
2. 2/1 so run is 1
3. its positive since slope is positve
4. y int is when x is 0 and y has value so y int is 1
5. y=2x+1 since slope and y int
:D