Answer:
The population in 2039 would be;

<em>Note</em><em>: this value can be confirmed by using the spreadsheet to extrapolate values.</em>
Explanation:
Given that the population in 2019 was;

And the population in 2020 was;

The population growth can be modeled with a linear equation;

The slope m is given as;

And b would be the value of y at x=0.
where x is the number of years after 2019;

the model can then be written as;

At year 2039, x would be;

substituting the value of x into the model;

Therefore, the population in 2039 would be;

<em>Note: this value can be confirmed by using the spreadsheet to extrapolate values.</em>