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3 years ago

10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

1 answer:

OLga [1]3 years ago

4 0

y^2(y^2+6) + 6(y^2+6)

(y^2+6)^2

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STALIN [3.7K]

Answer using quadratic formulae=5/4 and -4

6 0

3 years ago

Solve the equation 7x - 4 =4x -1

algol13

Answer:

x= 1

Step-by-step explanation:

7x-4x= -1+4

3x = 3

x= 1

7 0

3 years ago

Read 2 more answers

If the coordinates for C' are (4.5, 4.5), which rule best represents the dilation that was applied to rectangle ABCD to create r

Dmitry_Shevchenko [17]

The dilation of rectangle ABCD to create rectangle A'B'C'D' would change the size of the rectangle

The dilation rule is: (x,y) -> k(x,y)

<h3>How to determine the rule of dilation?</h3>

The coordinates of C' is given as:

C' = (4.5, 4.5)

The coordinate of point C is not given.

So, I will apply a general rule

The general rule of dilation is:

(x,y) -> k(x,y)

Where k represents the scale factor.

Assume that k = 3, the the rule would be
(x,y) -> 3(x,y)

Read more about dilation at:

brainly.com/question/3457976

7 0

2 years ago

Which of the following is the solution to the equation 25(z − 2) = 125? (6 points)

makvit [3.9K]

Answer:

z=7

Step-by-step explanation:

25(−2)=125

25−50=125

3 0

3 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago