Answer:
The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 14 - 1 = 13
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 3.0123
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 224.85 = $439.29
The upper end of the interval is the sample mean added to M. So it is 664.14 + 224.85 = $888.99.
The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).
The midpoint is (7,4.75) so the y-coordinate should be y=4.75. I hope that helps
Answer: positive
Step-by-step explanation: it’s positive because if you multiply two negative numbers they cancel each other out and it makes a positive number
Answer:
Step-by-step explanation:
So the point-slope formula looks like this: 
= any y point on the line
= any x point on the line
= the slope
And hey, look, we're already given all that information!
So we can just plug those values into the equation:
(*note: It's a +3.2 because 3.2 was negative in the first place, and -(-x) = +x)
According to Remainder Theorem for the polynomials, for every polynomial P(x) there exist such polynomials G(x) and R(x), that 
.
When the polynomial in P(x) is divided by (x + a), then there exist such polynomials G(x) and R(x), that P(x)=(x+a)G(x)+R(x). Note that for x=-a:
P(-a)=(-a+a)G(-a)+R(-a)=0·G(a)+R(-a)=R(-a).
This means that P(-a) is the remainder, not P(a).
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Answer:<span> correct choice is B.</span></span>
