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N76 [4]
1 year ago
5

Solve:

Mathematics
1 answer:
drek231 [11]1 year ago
5 0

The solutions to the inequalities are x >1 and x < 6

<h3>How to solve the inequalities?</h3>

The inequality expression is given as:

-2x + 5 < 3x + 10

Collect the like terms in the above inequality

-2x - 3x < 10 - 5

Evaluate the like terms

-5x < 5

Divide by -5

x >1

Also, we have

5(x - 2) <3x + 2

Open the bracket

5x - 10 < 3x + 2

Evaluate the like terms

2x < 12

Divide by 2

x < 6

Hence, the solutions to the inequalities are x >1 and x < 6

Read more about inequalities at

brainly.com/question/24372553

#SPJ1

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Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
3 years ago
Pls help me help my little cuz to understand pls BONUS POINTS!
aliya0001 [1]
Which part do you need help on?
7 0
2 years ago
Read 2 more answers
Solve the system of equations using substitution:<br> 6x – y = –15<br> X + 2y = 17
defon

Answer:

x = -1

y = 9

Step-by-step explanation:

jggchgcjgjcgjcgjcgjcgjcgjcgjc

3 0
3 years ago
Please help me find the answer
MatroZZZ [7]

Answer:

use calculator

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose that 37% of college students own cats. If you were to ask random college students if they own a cat what would the proba
Likurg_2 [28]

Using the binomial distribution, the probabilities are given as follows:

a) 0.37 = 37%.

b) 0.5065 = 50.65%.

c) 0.3260 = 32.60%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the fixed parameter is:

p = 0.37.

Item a:

The probability is P(X = 1) when n = 1, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{1,1}.(0.37)^{1}.(0.63)^{0} = 0.37

Item b:

The probability is P(X = 3) when n = 3, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.37)^{3}.(0.63)^{0} = 0.5065

Item c:

The probability is P(X = 2) when n = 4, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.37)^{2}.(0.63)^{2} = 0.3260

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
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