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melisa1 [442]
2 years ago
12

What is the value of log(x exponent 2 y exponent 3 divided by z) when given the following:

Mathematics
1 answer:
Gekata [30.6K]2 years ago
7 0

Answer:

B. 13

Explanation:

\sf\:Given\:expression: log(\dfrac{x^2 y^3}{z} )

Logarithm rules:

\sf (i)  \ \sf log(ab) = log(a) + log(b)\\ \\ (ii) \  log(a/b) = log(a) - log(b)\\\\ (iii) \ log(a^n) = n log(a)

Breakdown of the expression:

\rightarrow \sf log\left(\dfrac{x^2y^3}{z}\right)

\rightarrow \sf log\left(x^2\right) + log\left(y^3\right) - log(z)

\rightarrow \sf 2\log\left(x\right)+3\log \left(y\right)-\log \left(z\right)

insert given values

\rightarrow \sf 2(3)+3(2)-(-1)

\rightarrow \sf 13

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A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the se
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L = 2*√2

w = √2

Step-by-step explanation:

Given:

A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the semicircle.

Find:

What are the dimensions of the rectangle with maximum​ area?

Solution:

- Let the length and width of the rectangle be L and w respectively.

- We know that Length L lie on the diameter base. So , L < 4 and the width w is less than 2 . w < 2.

- Using the Pythagorean Theorem, we relate the L with w using the radius r = 2 of the semicircle.

                           r^2 = (L/2)^2 + (w)^2

                           sqrt (4 - w^2 ) = L / 2

                           L = 2*sqrt (4 - w^2 )           L < 4 , w < 2

- The relation derived above is the constraint equation and the function is Area A which is function of both L and w as follows:

                          A ( L , w ) = L*w

- We substitute the constraint into our function A:

                          A ( w ) = 2*w*sqrt (4 - w^2 )

- Now we will find the critical points for width w for which A'(w) = 0

                         A'(w) = 2*sqrt (4 - w^2 ) - 2*w^2 / sqrt (4 - w^2 )  

                         0 = [2*sqrt (4 - w^2 )*sqrt (4 - w^2 )   - 2*w^2] / sqrt (4 - w^2 )  

                         0 = 2*(4 - w^2 )   - 2*w^2

                         0 = -4*w^2 + 8

                         8/4 = w^2

                         w = + sqrt ( 2 )   ..... 0 < w < 2

- From constraint equation we have:

                          L = 2*sqrt (4 - 2 )

                          L = 2*sqrt(2)

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4 years ago
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