Let there exists a point (x, y) on the given line.
Slope of all points must be same, as they lie on the same line.
=> (y - 1)/(x - 2) = (4 - 1)/(-4 - 2)
=> (y - 1)/(x - 2) = - 1/2
=> y - 1 = (-½) (x - 2)
Option 1 is the correct option
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒ 
Now let 
∵ 
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
In getting the area of and equilateral triangle, you must first consider that all of its sides are congruent and that is 3 inches, so the formula in getting the area is height form its base so in getting its height you must use the pythagorean theorem by dividing the triangle so the hypotenuse of it is 3 and the base of 1.5inches, so the height is 4.77 inches then the area is 7.15 sqr.inch
Bro I’m trying to figure this out on my own test
Answer:
37 meters
Step-by-step explanation:
The equation for the area of a trapezoid is
.
Here,
,
, and
is unknown.




The height of the trapezoid is the width of the garden, so the garden is 37 meters wide.