Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
__
In many cases, it is preferred to keep the power inside the radical symbol.
The answer is -7 :) hope this helps
Answer: 43.6 (Rounded to the tenth)
Explanation: Use the method of: SOH CAH TOA.
Using TOA, T = Tangent.
tan(71) = x/15. Using the butterfly method you can just do the following equation:
15 tan(71) = 43.56 (Rounded to tenth) —> 43.6
Answer:
blue green and yellow
Step-by-step explanation:
solving a linear equation we conclude that the value of x must be 6.
<h3>
How to find the value of x?</h3>
On the statement we have the relations:
AB = BC
BC = CD
For the transitive property, then we have that:
AB = CD
Replacing the equations in the image, we get:
2x + 1 = 4x - 11
Solving this linear equation for x we get:
1 + 11 = 4x - 2x
12 = 2x
12/2 = x
6 = x
So yes, solving that linear equation we conclude that the value of x must be 6.
Learn more about linear equations:
brainly.com/question/1884491
#SPJ1