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3 years ago

How to calculate the mode of this data? 1.7 8.9 3 5.9 3.2 4.1 6.6 0.7

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

There is No mode of the data set.

Step-by-step explanation:

We need to calculate the mode of the data: 1.7,8.9,3, 5.9, 3.2, 4.1, 6.6, 0.7

Mode: The most repeating value in the data set is called Mode.

Since in the given data set, there is no repeating value so there is no mode in the data set.

Keywords: Mode of Data

Learn more about Mode of Data at:

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The texture in this Klimt painting is?

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Answer: i think its implied

Step-by-step explanation:

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3 years ago

Read 2 more answers

20. A cement mixer held 6 3/4 tons of cement. Ms. Folley used 2/3 of the cement for her driveway. How many tons of cement remain

NNADVOKAT [17]

Answer:

6 2/25 tons cement

Step-by-step explanation:

If cement mixer held 6 3/4 tons=6.75 tons

Mr. Folley used=0.67

After use cement are=6.75-0.67=6.08

So,

0.08=2/25

That's why answer is 6 2/25 tons

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3 years ago

Which is another way to write 42+63?

eduard

Forty two plus sixty three that's your answer

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3 years ago

In 6 years, John will be 3 times the age he was 2 years ago. What is his current age?

Vladimir79 [104]

Answer:

John is currently 6 years old.

Step-by-step explanation:

2 years ago: x years

Current time: x+2

In 6 years: x+8

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(subract x from both sides)

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Therefore, John is 6 years old in current time

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3 years ago

A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a

storchak [24]

Answer: 267.

Step-by-step explanation:

When there is no prior information for the population proportion, then the formula we use to find the sample size to estimate the confidence interval :

$n=0.25(\dfrac{z^*}{E})^2$ , where z* = Critical z-value and E + amrgin of error.

Let p = proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label.

Since , we have no prior information about p. so we use above formula

with E = 0.06 and critical value for 95% confidence =z* =1.96 [By z-table ] , we get

$n=0.25(\dfrac{1.96}{0.06})^2=0.25(32.6666)^2\\\\=(0.25)(1067.111111)\\\\=266.777777778\approx267$

Hence, the required sample size is 267.

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3 years ago