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LekaFEV [45]
3 years ago
5

How to calculate the mode of this data? 1.7 8.9 3 5.9 3.2 4.1 6.6 0.7

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

There is No mode of the data set.

Step-by-step explanation:

We need to calculate the mode of the data: 1.7,8.9,3, 5.9, 3.2, 4.1, 6.6, 0.7

Mode: The most repeating value in the data set is called Mode.

Since in the given data set, there is no repeating value so there is no mode in the data set.

Keywords: Mode of Data

Learn more about Mode of Data at:

  • brainly.com/question/10689103
  • brainly.com/question/13174282
  • brainly.com/question/5069437

#learnwithBrainly

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Which expressions are equivalent to the expression 7(5 + m) - 8?
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Answer:

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Step-by-step explanation:

7(5 + m) - 8

open the bracket:

= 35 + 7m - 8 \\  = 27 + 7m

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2 years ago
Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

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  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

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Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

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Answer:

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Step-by-step explanation:

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