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Helen [10]
2 years ago
11

What is the reference angle of -139 degrees

Mathematics
2 answers:
katrin [286]2 years ago
6 0

41º

1) Since we want to find the reference angle for a -139º angle, we need to resort to the following formula

Reference\:Angle\:\:Quadrant\:III=180^{\circ}-139^{\circ}=41^{\circ}

2) Note that a -139 angle is in quadrant III, since negative angles are clockwise oriented

3) Thus the Reference Angle is 41º

Morgarella [4.7K]2 years ago
4 0

Answer:

41°

Step-by-step explanation:

Find the acute angle in the first quadrant used as a reference for

−139°.

41°

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129.5 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h(a + b)

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Here h = 7, a = 15 and b = 22 , thus

A = \frac{1}{2} × 7 × (15 + 22)

   = 0.5 × 7 × 37

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85/7=12 with a remainder of 1

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3 years ago
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I don’t know if you want both but I’m going to give you both.

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Find the following product if possible. Explain if it is not possible. <br><br> (See picture)
Nataly_w [17]

Answer:

The answer to your question is the letter a

Step-by-step explanation:

 |    1    4    -1   |      |  2    -1   |

 |    3   2    2   |      |  0     3  |         Product  = 2 x 3   and 3 x 2  = 2 x 2

                              | 5     2  |          It is possible to do this product,

                                                      the result will be a 2 x 2 matrix

Process

1.- Multiply first row by first column and second row by second column.

2.- Multiply the second row by the first column and second row by the second column.

  = (1 x 2) + (4 x 0) + (-1 x 5) = 2 + 0 - 5 = -3

  = (1 x -1) + (4 x 3) + (-1 x 2) = -1 + 12 - 2 = 9

  = (3 x 2) + (2 x 0) + (2 x 5) = 6 + 0 + 10 = 16

  = (3 x -1) + (2 x 3) + (2 x 2) = -3 + 6 + 4 = 7

Result

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             | 16   7  |    

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