The city is planning to install streetlights and wants five lights along a walkway of 60 yards. if there is a light at the begin
ning and at the end of the walkway and the lights are evenly spaced, what is the distance between each light
1 answer:
If you try to imagine a walkway has a total of 60 yards starting from the first streetlight down to the last streetlight. Knowing that there are a total of five streetlights all in all, that means there are only 3 left to space evenly between the first and the last streetlight. Consequently, there would be four spaces all in all. Please see the picture so that you would understand better.
That means there are 4 evenly spaced lengths measuring to x yards. Therefore,
x = 60/4 = 15 yards
The distance between each light is 15 yards.
That means there are 4 evenly spaced lengths measuring to x yards. Therefore,
x = 60/4 = 15 yards
The distance between each light is 15 yards.
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Answer:
a) Binomial distribution B(n=12,p=0.01)
b) P=0.007
c) P=0.999924
d) P=0.366
Step-by-step explanation:
a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.
b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.
Then,
c) In this case, the distribution is B(1200,0.01)
d) In this case, the distribution is B(100,0.01)
We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.