First convert everything into inches.

1 foot = 12 in
5 feet = 5*12 = 60 in
12 feet = 12*12 = 144 in

Now add them together

60 + 9 + 144 + 3 = 216 in

or

18 feet

Hope this helps :)

4 0

3 years ago

HELPPPPPPPPPP MEEEEEEEEE IM TO YOUNG TO DIE

Zanzabum

Answer:

Im either gonna say, the last one or the first. Please dont hate me.

8 0

3 years ago

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równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

2 years ago

Triangle ABC is reflected to form Triangle A’B’C

SVEN [57.7K]

Answer:

I believe it is reflection across the x axis.

Callie

P..S Are you in k12

Step-by-step explanation:

4 0

3 years ago

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