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Over [174]
2 years ago
15

Given the equation below, find the x and y−intercepts by completing the table.What is the problem with using these intercepts to

graph the equation in #7?The ordered pair (x, y) you found in #7 is called the

Mathematics
1 answer:
kvasek [131]2 years ago
5 0

-4x+2y=0

In order to find the x-intercept we need to make y=0

-4x+2(0)=0

Then we isolate the x

-4x=0x=0

x y Ordered Pair type of intercept

0 0 (0,0) x-intercept

Now for the y-intercept we need to make x=0

-4(0)+2y=0

we isolate the y

2y=0

y=0

0 0 (0,0) y-intercept

ANSWER

0 0 (0,0) x-intercept

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Answer:

Here, D>0, hence the quadratic equation has two distinct real roots.

Step-by-step explanation:

Given quadratic equation is 6x^{2} +10x-1.

Let, the quadratic equation is ax^{2} +bx+c    [where, a,b,c are the constants]

The Discriminant (D)=b^{2}-4ac

Case 1:   b^{2}-4ac>0, if the discriminant is greater than 0, it means the quadratic equation has two real distinct roots.

Case 2: b^{2}-4ac, if the discriminant is less than 0, it means the quadratic equation has no real roots.

Case 3: b^{2}-4ac=0, if the discriminants is equal to 0, it means the quadratic equation has two real identical roots.

Now,

      we have 6x^{2} +10x-1, where a=6,b=10,\ and\  c=-1

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