Answer:
<u>Option 3:</u> 8 Superscript StartFraction x Over 3 EndFraction
Step-by-step explanation:
RootIndex 3 StartRoot 8 EndRoot Superscript x
<u>Options</u>:
RootIndex x StartRoot 8 EndRoot Superscript x
8 Superscript StartFraction 3 Over x EndFraction
8 Superscript StartFraction x Over 3 EndFraction
8 Superscript 3 x
Answer: 1.5
Step-by-step explanation:
From the attached graph:
D = (0, 4)
F = (3, 2)
After segment DF was dilated from the origin to create segment D'F'
D' = (0, 6)
F' = (4.5, 3)
Scale factor is obtained by calculating the proportion of the coordinates of the two segments. That is ;
Scale factor = value on dilated coordinate / value on original coordinate
Taking the x-coordinate of F and F':
Scale factor = coordinate 'x' of F' / coordinate 'x' of F
Scale factor = 4.5 / 3 = 1.5
Similarly,
Taking the y-coordinate of F and F':
Scale factor = coordinate 'y' of F' / coordinate 'y' of F
Scale factor = 3 / 2 = 1.5
Answer:
The position of Michael's hands relative to the surface of the water is -<u>1.3 meters</u>.
Step-by-step explanation:
<u><em>The question is incomplete, so below is the complete question?</em></u>
<em>Michael is doing an underwater handstand. His feet are sticking up 0.5 meters above the surface of the water. Michael's hands are 1.8 meters directly below his feet. What is the position of Michael's hands relative to the surface of the water?</em>
Now, to find the position of Michael's hands relative to the surface of the water.
Meters of Michael's hands directly below his feet = 1.8 meters.
Meters of his feet sticking above the surface of the water = 0.5 meters.
So, to get the position of Michael's hands relative to the surface of the water we subtract meters of Michael's hands directly below his feet from meters of his feet sticking above the surface of the water:
Therefore, the position of Michael's hands relative to the surface of the water is -1.3 meters.