Heat from condition A and condition B at constant pressure =
= 31.9kJ
First pathway is: A (3. 00 atm, 20. 0 L) to C (1. 00 atm, 20. 0 L) to D (1. 00 atm, 50. 0 L)
Second pathway is: A (3. 00 atm, 20. 0 L) to B (3. 00 atm, 50. 0 L) to D (1. 00 atm, 50. 0 L)
Temperature at condition A:
= 731k
Temperature at condition B:
= 731K x 50.0L/20.0L
= 1828K
Heat from condition A and condition B at constant pressure:
ΔT
= n (3.5R)ΔT
= 1mol x (3.5 x 8.314J/molK)(1828K - 731K) x 0.001KJ/J
Heat = = 31.9Kj
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