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svp [43]
1 year ago
7

Solve for A, find the exact value of each expression below.

Mathematics
1 answer:
nataly862011 [7]1 year ago
4 0
\begin{gathered} \theta=\frac{7\pi}{6} \\ 2\sin (\frac{7\pi}{6})=2(\frac{-1}{2})=-1 \\ 2\sin (\frac{7\pi}{6})=-1 \\  \\ \sin ^2(\frac{7\pi}{6})=(\frac{-1}{2})^2=\frac{1}{4} \\ \sin ^2(\frac{7\pi}{6})=\frac{1}{4} \\  \\ \sin (-\frac{7\pi}{6})=-\sin (\frac{7\pi}{6})=-(\frac{-1}{2})=\frac{1}{2} \\ \sin (-\frac{7\pi}{6})=\frac{1}{2} \end{gathered}

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If 100 people drink 1.5 cups of coffee a day and the cost per cup is .40 how much would it cost to provide coffee for the whole
N76 [4]

Answer:

It would cost <u>15600</u> to provide coffee for the whole year.

Step-by-step explanation:

Given:

If 100 people drink 1.5 cups of coffee a day and the cost per cup is .40

Now, to find the cost to provide coffee for the whole year if you're place is open 5 days a week.

So, we have the unit rate, and we have to find the cost of 1.5 cup by multiplying 0.40.

<em>1.5 cup of coffee cost </em>1.5\times 0.40=0.60.

<em>Thus, 1.5 cup cost 0.60.</em>

<em>If, 100 people drink 1.5 cups. </em>

<em>Then, total cost of  100 people drinking 1.5 cups of coffee = </em>100\times 0.60=60<em />

<em>As, place is open 5 days a week.</em>

So, to get the cost of coffee in 5 days of a week we multiply 5 by 60:

5\times 60\\\\=300.

<em>Hence, the cost of coffee in a week is 300.</em>

<em>In 1 year there are 52 weeks.</em>

Now, to get the cost for the whole year we multiply 52 by 300:

52\times 300\\\\=15600.

Therefore, it would cost 15600 to provide coffee for the whole year.

6 0
3 years ago
Read 2 more answers
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Let f(x)=5/x and g(x) =2x^2+5x. What two numbers are not in the domain of F o G?
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6 0
2 years ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

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The company sells Mr. Brophyan insurance policy and he has an accident.

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We have to find P(E_1/A)

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P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

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gayaneshka [121]

Answer:

Improper Fractions:

Step-by-step explanation:

1. 2 and 2/3

2. 2 and 1/4

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