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svp [43]
1 year ago
7

Solve for A, find the exact value of each expression below.

Mathematics
1 answer:
nataly862011 [7]1 year ago
4 0
\begin{gathered} \theta=\frac{7\pi}{6} \\ 2\sin (\frac{7\pi}{6})=2(\frac{-1}{2})=-1 \\ 2\sin (\frac{7\pi}{6})=-1 \\  \\ \sin ^2(\frac{7\pi}{6})=(\frac{-1}{2})^2=\frac{1}{4} \\ \sin ^2(\frac{7\pi}{6})=\frac{1}{4} \\  \\ \sin (-\frac{7\pi}{6})=-\sin (\frac{7\pi}{6})=-(\frac{-1}{2})=\frac{1}{2} \\ \sin (-\frac{7\pi}{6})=\frac{1}{2} \end{gathered}

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Answer:

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RUDIKE [14]

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3 years ago
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3 years ago
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sveticcg [70]

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