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kkurt [141]
3 years ago
8

A scientist measured a museum specimen. She recorded the measurement as 75 centimeters. What could the scientist have been measu

ring? length of a dinosaur bone
mass of a dinosaur bone
length of a gem
mass of a gem​
Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

75cm is the measurment

Step-by-step explanation:

It would have had to have been the lenght of the gem because 75cm or 75 centimeters is a measurment not the mass of something. The mass is the amount of matter in an object.

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D) (K<br> If f(x) = x3 and g(x) = 2x + 7, what is g(x)<br> when x = 2?
nadya68 [22]

Answer:

11

Step-by-step explanation:

g(x) = 2x + 7

Put x as 2 and evaluate.

g(2) = 2(2) + 7

Multiply.

g(2) = 4 + 7

Add the terms.

g(2) = 11

3 0
3 years ago
A juice shop needed 360 oranges to make 40 L of fresh squeezed juice how many oranges will be needed to make 60 L of fresh squee
marishachu [46]

Answer:

540 oranges

Step-by-step explanation:

360 Oranges=40L

40*3/2=60

360*3/2=540

5 0
3 years ago
Read 2 more answers
What type of triangle is shown here?
Naddika [18.5K]
Equilateral because all sides are equal
5 0
2 years ago
Help me please . quick :)
ycow [4]

Answer:

x= 1

QS = 10 cm

QRS = 40cm

Step-by-step explanation:

4x + 1 = 5x

x= 1 cm

QS = 4x + 1 + 5x

= 9x + 1

= 9 + 1

= 10cm

QRS perimeter

QS + RQ + RS but ( RQ = RS)

= 10 + 15 + 15

= 40cm

3 0
3 years ago
An art history professor assigns letter grades on a test according to the following scheme.A: Top 5% of scoresB: Scores below th
adoni [48]

Answer:

Grade B score:

76 \leq x \leq 89    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73.3

Standard Deviation, σ = 9.7

We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

B: Scores below the top 5% and above the bottom 62%

We have to find the value of x such that the probability is 0.62

P( X > x) = P( z > \displaystyle\frac{x - 73.3}{9.7})=0.62  

= 1 -P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.62  

=P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.38  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 73.3}{9.7} = 0.305\\\\x = 76.26  

We have to find the value of x such that the probability is 0.05

P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 73.3}{9.7} = 1.645\\\\x = 89.26  

Thus, the numerical value of score to achieve grade B is

76 \leq x \leq 89

7 0
3 years ago
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