Question

Find the probability distribution of getting sum when a spinner of 3 divisions, labeled from 1 to 3, is spun twice.

Answer 1

We are given that:

The spinner is a 3 divisions spinner. Numbering from 1-3

When the spinner is spun twice, the sum obtained will range from 2-6 as shown below:

$\begin{gathered} nth\colon Spin_1+Spin_2 \\ \\ 1st\colon1+1=2 \\ 2nd\colon1+2=3 \\ 3rd\colon1+3=4 \\ \\ 4th\colon2+1=3 \\ 5th\colon2+2=4 \\ 6th\colon2+3=5 \\ \\ 7th\colon3+1=4 \\ 8th\colon3+2=5 \\ 9th\colon3+3=6 \end{gathered}$

We can thus see the probability distribution from above (I will write it below):

$\begin{gathered} P(sum)=\frac{chance.of.outcome}{possible.outcome} \\ \\ P(2)=\frac{1}{9} \\ P(3)=\frac{2}{9} \\ P(4)=\frac{3}{9} \\ P(5)=\frac{2}{9} \\ P(6)=\frac{1}{9} \end{gathered}$

Therefore, the answer is the third option