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enyata [817]
1 year ago
5

Find the probability distribution of getting sum when a spinner of 3 divisions, labeled from 1 to 3, is spun twice.

Mathematics
1 answer:
Archy [21]1 year ago
4 0

We are given that:

The spinner is a 3 divisions spinner. Numbering from 1-3

When the spinner is spun twice, the sum obtained will range from 2-6 as shown below:

\begin{gathered} nth\colon Spin_1+Spin_2 \\  \\ 1st\colon1+1=2 \\ 2nd\colon1+2=3 \\ 3rd\colon1+3=4 \\  \\ 4th\colon2+1=3 \\ 5th\colon2+2=4 \\ 6th\colon2+3=5 \\  \\ 7th\colon3+1=4 \\ 8th\colon3+2=5 \\ 9th\colon3+3=6 \end{gathered}

We can thus see the probability distribution from above (I will write it below):

\begin{gathered} P(sum)=\frac{chance.of.outcome}{possible.outcome} \\  \\ P(2)=\frac{1}{9} \\ P(3)=\frac{2}{9} \\ P(4)=\frac{3}{9} \\ P(5)=\frac{2}{9} \\ P(6)=\frac{1}{9} \end{gathered}

Therefore, the answer is the third option

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
<br> .........help.......me.......please
AlexFokin [52]

Answer:

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Step-by-step explanation:

4 0
3 years ago
A bottle of the medicine contains 0.5 kilograms of the medicine. One dose of the medicine is 20 grams for a child and 45 grams f
victus00 [196]
1.48 more grams of the medicine will be needed
5 0
3 years ago
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Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movi
ruslelena [56]

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

<em><u>Solution:</u></em>

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

<em><u>Therefore, we can frame a equation as,</u></em>

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

3 \times d + 10 \times p = 54.50

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

9 \times d + 5 \times p = 57.25

9d + 5p = 57.25 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

<em><u>Substitute p = 4.25 in eqn 1</u></em>

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

4 0
3 years ago
The shaded portion of the grid below represents the portion of a granola bar remaining.
Nady [450]

Answer:

A. 1%

B. 80%

C. 0.8, 8/10

Step-by-step explanation:

A. There are 100 blocks so each block is 1/100 which is 1%

B. As you can see, there are 80 blocks shaded so that would be 80/100 which is 80%

C. You can represent a percent as a decimal or a fraction

Hope this helped!

8 0
3 years ago
Read 2 more answers
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