Answer:
![y =5(3)^x](https://tex.z-dn.net/?f=y%20%3D5%283%29%5Ex)
Step-by-step explanation:
Given
The attached table
Required
Determine the equation of the table
The table represents an exponential function. So, we make use of
![y = ab^x](https://tex.z-dn.net/?f=y%20%3D%20ab%5Ex)
When x = 0, y= 5.
So:
becomes
![5 = ab^0](https://tex.z-dn.net/?f=5%20%3D%20ab%5E0)
![5 = a*1](https://tex.z-dn.net/?f=5%20%3D%20a%2A1)
![5 = a](https://tex.z-dn.net/?f=5%20%3D%20a)
![a = 5](https://tex.z-dn.net/?f=a%20%3D%205)
When x = 1; y = 15
So;
becomes
![15 = a * b^1](https://tex.z-dn.net/?f=15%20%3D%20a%20%2A%20b%5E1)
![15 = a * b](https://tex.z-dn.net/?f=15%20%3D%20a%20%2A%20b)
Substitute 5 for a
![15 = 5 * b](https://tex.z-dn.net/?f=15%20%3D%205%20%2A%20b)
Divide both sides by 5
![\frac{15}{5} = \frac{5 * b}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B5%7D%20%3D%20%5Cfrac%7B5%20%2A%20b%7D%7B5%7D)
![3 = b](https://tex.z-dn.net/?f=3%20%3D%20b)
![b = 3](https://tex.z-dn.net/?f=b%20%3D%203)
Substitute values for a and b in: ![y = ab^x](https://tex.z-dn.net/?f=y%20%3D%20ab%5Ex)
![y =5(3)^x](https://tex.z-dn.net/?f=y%20%3D5%283%29%5Ex)
Answer:
C
Step-by-step explanation:
Find P(X > 67)
using ( x - mean )/ standard deviation again you will get thi(1) which is equal to 0.8413....
0.8413 x 5000 is 4207
A larger interval is wider than a smaller interval.
The correct equation is P(t) = Po*e^(kt). Please enclose "kt" inside parentheses and use the " ^ " symbol to indicate exponentiation.
"k" is the growth constant, which here is 0.017. "t" is the number of yeasrs. P(7) is the population after 7 years. Po is the initial population, which in this case is 91 million.
The initial value, when t = 0, is 91 million.
After 7 years, the population, P(7), was P(7) = (91 million)*e^(0.017*7). This evaluates to P(7) = (91 million)*(1.070) = 96 million