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Ostrovityanka [42]
1 year ago
15

How do you find the point that is equidistant from the three vertices of a triangle?

Mathematics
1 answer:
Vedmedyk [2.9K]1 year ago
3 0

Answer:

In a right triangle, the mid–point of the hypotenuse is equidistant from the three vertices of triangle.

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The distance between 5,3 and 1,3
mel-nik [20]

Answer:

(4,0)

Step-by-step explanation:

(5,3) (1,3)

You need to subtract from the x axis on both coordinates and the y axis in both coordinates.

(5-1) (3-3)

(4,0)

I also checked on a graph as well, so it's correct.

4 0
3 years ago
20 points ! !!! 3. Write an equation in which the quadratic expression 2x^ -2x -12 equals 0. Show the expression in factored for
Tpy6a [65]

Answer:

see below

Step-by-step explanation:

2x^2 -2x-12 = 0

Factor out 2

2(x^2 - x -6) = 0

Factor inside the parentheses

2( x-3)(x-2)=0

Using the zero product property

x-3 =0   x-2=0

x=3   x=2

The graph crosses the x axis when x=3 and x=2

3 0
4 years ago
Find vertex of g(x)=21​(x−8)^2−8
Orlov [11]

Answer:

vertex at (8, -8)

Step-by-step explanation:

find vertex of g(x)=21​(x−8)^2−8

this is in vertex form

if you recall the formula:    f(x) =   a (x - h)^2  + k

(h, k) is the vertex.

so here we see  h = 8 and k = -8

so vertex at (8, -8)

7 0
3 years ago
Work out the height of this cone
Blababa [14]

Answer:20 cm

Step-by-step explanation:

Volume of cone=540π

Radius=r=9

Volume of cone=1/3 x π x r^2 x h

540π=1/3 x π x 9^2 x h

540π=1/3 x π x 9 x 9 x h

540π=(1xπx9x9xh)/3

540π=(81πh)/3

540π=27πh

Divide both sides by 27π

540π/27π=(27πh)/27π

20=h

h=20

Height =20 cm

6 0
3 years ago
What is the answer to this problem? Try to describe as much as you can.
Zinaida [17]

Answer:

On the grid

Step-by-step explanation:

Go 226 spaces to the left of the x axis, when you get there go 216 up on the y axis

8 0
4 years ago
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