Answer:
nah its not cause in radical form that bih is 5√5
Step-by-step explanation:
It is not a function—an element from the domain is paired with more than one element from the range. Specifically, the input value of 4 corresponds to two output values: 5 and -4.
A function can only take on one output for each input. It only takes one input value to associate with more than one output value to be invalid as a function.
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Answer:
C. In y^2-y=6, 6 should have been subtracted on both sides first.
Step-by-step explanation:
It is a quadratic equation so you subtract the 6 and create
y^2-y-6=0
Then you factor it to:
(y-3)(y+2)=0
The solutions then are:
y-3=0, y=3 and y+2=0, y=-2
{-2,3}
Slope= 4
Y intercept = -2
