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mario62 [17]
1 year ago
7

In a game, three fair number cubes with faces numbered 1 through 6 are rolled. If the sum of the cubes is 16 or greater, a playe

r wins 432 tokens; otherwise, the player wins nothing. Based on the given information, which number is equivalent to the fair number of tokens to pay for playing this game? A.8 B.12 C.14D.20
Mathematics
1 answer:
alukav5142 [94]1 year ago
6 0

Solution

For this case the total outcomes are 6*6*6 = 216

The expected value is given by:

E(x) = p* X1 + (1-p)*X2

Where p = probability of success (sum of cubes 16 or greater)

and 1-p = probability of failure

X1 =

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A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for ππ .. 4 in L, Base
SCORPION-xisa [38]
Check the picture below.

4 0
4 years ago
Read 2 more answers
A rental car company has noticed that the distribution of the number of miles customers put on rental cars per day is skewed to
kodGreya [7K]

Using the Central Limit Theorem, the correct option is:

(c) Average number of miles put on a rental car per day across 25 customers.

--------------------------

The Central Limit Theorem states that, for a normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means of size m are approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

  • The interpretation related to this problem is that the larger the sample size, the smaller the standard deviation.
  • Thus, among the options, the largest sample is 25, thus, option c will have the smallest standard deviation.

A similar problem is given at brainly.com/question/23088374

5 0
2 years ago
The exponential decay graph shows the expected depreciation for a new boat, selling for $3500, over 10 years a. Write an exponen
Alex Ar [27]
For the answer to the question above,  
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years. 
V(0) = 3500 
V(2) = 2000 

n = 0 
V(0) = a * b^0 = 3500 
a = 3500 

V(2) = a * b^2 
2000 = 3500 * b^2 
b = sqrt (2000/3500) 
b ≈ 0.76 

V(n) = 3500 * 0.76^n 

We can check it for n = 1 which is close to 2500 in the graph: 
V(1) = 3500 * (0.76)^1 
V(1) = 2660 

And in the graph we have V(3) ≈ 1500, 
V(n) = 3500 * (0.76)^3 ≈ 1536 

Now n = 9.5 
V(9.5) = 3500 * (0.76)^(9.5) 
V(9.5) ≈ 258</span>
4 0
4 years ago
Read 2 more answers
A sample of 50 impossible whoppersandwiches have a mean fat content of 37.6g and standard deviation of 4.9g . A sample of 58 reg
cluponka [151]

Answer:

Step-by-step explanation:

H0: μ1____ μ2For Q17(circle one: equal to, <u>less than or equal to</u>, greater than or equal to, not equal to )

H1 : μ1____ μ2For Q18(circle one: equal to, less than, <u>greater than</u>, not equal to )

Formula for calculating the the test:

t = [ (x₁ - x₂) - d ] / sqrt[(s₁²/n₁) + (s₂²/n₂)]

where x₁ = 37.6, x₂ = 39.3, d = 0 assuming equality = 37.6 - 39.3 = -1.7

s₁² = 4.92 = 24.01, s₂² = 2.72 = 7.29, n₁ = 50, n₂ = 58.

thus, t = [ (-1.7) - (0)] / √(24.01/50) + (7.29/58)

    t = (-1.7) / (0.4802 + 0.1257)

   t = -1.7 / 0.6059

   t = -2.8057. = -2.81

P value:

Lets find the degree of freedom:

DF = (s₁²/n₁ + s₂²/n₂)² / { [ (s₁² / n₁)² / (n₁ - 1) ] + [ (s₂² / n₂)² / (n₂ - 1) ] }

DF = (24.01/50 + 7.29/58)² / {[(24.01 / 50)² / 50-1)] + (7.29/58)² / 58-1)]}

DF = (0.4802 + 0.1257)² /{[ (0.4802)²/49] + (0.1257)²/57)]}

DF = (0.6059)²/ (0.00471 + 0.00028)

DF = 0.3671 / 0.00499 = 75.37

Thus, P value = 0.9968 using a t distribution calculator.

Decision/Conclusion: Since the P value 0.9968 is greater than α (.05), Fail to Reject H0, There is not sufficient evidence to warrant the rejection of the claim.

4 0
3 years ago
I need help with this asap !!
maxonik [38]

Answer:

x^2-2x-13

Step-by-step explanation:

f(x) = 2x-5

g(x) = x^2 -4x-8

f(x) +g(x) = 2x-5 +  x^2 -4x-8

Combine like terms

              = x^2+2x-4x-5-8

               =x^2-2x-13

3 0
3 years ago
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