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cestrela7 [59]
3 years ago
14

A bag contains three yellow tickets numbered on to three. The bag also contains four green tickets numbered one to four. What is

the probability of randomly picking a ticket that is yellow or has an even number?​
Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0
6/7 because there are 7 tickets in total and 3 of them are yellow and 3 of them have even numbers.
erik [133]3 years ago
4 0

Answer:

6/7

Step-by-step explanation:

yellow = 3

even =3

3+3=6

n(s)=7 so 6/7

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Answer given below.

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3 years ago
<img src="https://tex.z-dn.net/?f=8%28%20%7B4%7D%5E%7B2%7D%29%20%2B%20%20%7B2%7D%5E%7B4%7D%20" id="TexFormula1" title="8( {4}^{2
cluponka [151]

The given expression 8(4)^2+2^4 is equal to 144 or 12^2

<em><u>Solution:</u></em>

Given expression is:

8(4)^2+2^4

We have to evaluate the above given expression

We know that,

(4)^2 = 4 \times 4 = 16

2^4 = 2 \times 2 \times 2 \times 2=16

Substituting these in above given expression, we get

8(4)^2+2^4=8 \times 16+16\\\\8(4)^2+2^4= 128+16\\\\8(4)^2+2^4=144

Also we know that,

12 \times 12 = 144

Therefore,

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