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Sedbober [7]
1 year ago
11

Write the parts of the triangle XYZ that are congruent to triangle PQR

Mathematics
2 answers:
timofeeve [1]1 year ago
7 0

Answer:

PQ=xy ( side)

PR=xz. (side)

QR=yz. (side)

Zolol [24]1 year ago
6 0

Answer:

PQ=xy ( side)

PR=xz. (side)

QR=yz. (side)

Step-by-step explanation:

PQ=xy ( side)

PR=xz. (side)

QR=yz. (side)

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24. 17 is 40% of what number?
EastWind [94]

Answer:

9.7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
Multiple choice please help!!
AveGali [126]

3 and 4

Step-by-step explanation:

y=5x

y=5(0)

y=0

y=5x

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y=50

y=5x

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y=255

y=5x

y=5(400)

y=2000

5 0
3 years ago
Solve –15 = 4m – 7.<br><br><br> –32<br><br> 2<br><br> –12<br><br> –2
Shkiper50 [21]

Answer:

-2 =m

Step-by-step explanation:

–15 = 4m – 7

Add 7 to each side

–15+7 = 4m – 7+7

-8 = 4m

Divide each side by 4

-8/4 = 4m/4

-2 =m

4 0
3 years ago
:( help? please.. i need help
Oduvanchick [21]
The answer is 64 because they are alternate interior angles. Alternate interior angles are always congruent.
5 0
3 years ago
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