If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
The 3 goes with the square root you don’t need to multiply or anything like that. If you need to simply for example 3 square root of 20 which is when 3 is outside the square root sign. The 20 will be separated with 4*5 in the square root and then you will square root the 4 leaving the 5 in and bringing 2 out. Now you can’t just bring it out and forget about the 3 outside you need to multiply that 2 and 3 and you get 6! So you final answer is 6 square root 5. Hope this helps reply if you have a question!
Answer:
Sorry, i dont know
Step-by-step explanation:
I dont know the answer to this question.....
