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f′(x)=2∗(8x(2−1))+1∗11x(1−1)
which is
f′(x)=16x+11
then let
x = 7 gives us
f′(7)=123
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<span>Hope my answer would be a great help for you. </span> </span>
<span> </span>
Answer:
B.
Step-by-step explanation:
Well we know that
so we can get the 2 outside of the radical
and we can get the x^2 outside too.
and we also can get y outside.
so we have:
![2x^{2}y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
P=3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−2=5p+3p−8−6p
−2=5p+3p+−8+−6p
−2=(5p+3p+−6p)+(−8)(Combine Like Terms)
−2=2p+−8
−2=2p−8
Step 2: Flip the equation.
2p−8=−2
Step 3: Add 8 to both sides.
2p−8+8=−2+8
2p=6
Step 4: Divide both sides by 2.
2p2=62
p=3
The answer is 3 because 1/3 of 3 is 1 and 1/3 of 9 is 3 and 3 times 1 is 3
Answer: 3
Step-by-step explanation:
5x - 2y
5(-2) - 2(-2)
-10 + 4
= - 6
