Ask question

Ask question

All categories

3 years ago

14

Which of these statements correctly compares probeware (such as an electronic temperature probe) to traditional analog tools (su

ch as a liquid-based thermometer)?
A Measurements by traditional analog tools are good to a larger number of significant figures.
B Measurements by traditional analog tools are less prone to experimental error.
C Probeware is typically very difficult to transport.
D Probeware is useful for obtaining many measurements in rapid succession.

2 answers:

Zina [86]3 years ago

8 0

Answer:

D) Probeware is useful for obtaining many measurements in rapid succession.

Step-by-step explanation:

We are required,

To compare probeware ( namely an electronic temperature probe) to traditional analog tools ( namely a liquid based thermometer).

Now, as we know,

<em>Probewares are generally used to collect precise data (with less amount of error) in real-time and analyze the result using powerful tools.</em>

So, we have,

Probewares are easy to use while being cost-effective.

Thus, the correct statement for the comparison would be,

D) Probeware is useful for obtaining many measurements in rapid succession.

guapka [62]3 years ago

4 0

Probeware is useful for obtaining many measurement in rapid succession, a function that an analog tool can not perform. The answer is D.

You might be interested in

What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =

FinnZ [79.3K]

Answer:

x = 12

Step-by-step explanation:

IMPORTANT: Both answers should add up to 180 if they dont you did it wrong!

(10x - 20) + (6x + 8 ) = 180 plug in 12 for both of them

(10 * 12 - 20) + 6 * 12 + 8) = 120

(120 - 20) + (72+ 8 ) = 180

(100) + (80) = 180

so x = 12

hope this helps please make brainliest

4 0

3 years ago

A triangular pyramid has a height of 18 yards and a base with an area of 330 square yards. What is the volume of the pyramid?

WITCHER [35]

Answer:

option C. $V=1,980\ yd^{3}$

Step-by-step explanation:

we know that

The volume of the triangular pyramid is equal to

$V=\frac{1}{3}Bh$

where

B is the area of the triangular base

h is the height of the pyramid

In this problem we have

$B=330\ yd^{2}$

$h=18\ yd$

substitute in the formula

$V=\frac{1}{3}(330)(18)=1,980\ yd^{3}$

3 0

3 years ago

Ayuda por favor! <br> Lo necesito urgente!!!

expeople1 [14]

Es hora be comer!!!!!

3 0

3 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago

Help asap please I'm stuck and I gotta leave soon

Darya [45]

Answer: I found the answer of A=9h

5 0

3 years ago

Read 2 more answers