At a gymnastics competition, Joey scored 9.4, 9.7, 9.9, and 9.8. Carlos scored 9.5, 9.2, 9.7, and 9.6. Who had the greater avera

Question

Nana76 [90]

2 years ago

13

At a gymnastics competition, Joey scored 9.4, 9.7, 9.9, and 9.8. Carlos scored 9.5, 9.2, 9.7, and 9.6. Who had the greater avera

ge score? By how many point was his score higher?

Mathematics

2 answers:

8090 [49] · Answer 1 · 2022-06-03T19:58:08+03:00

8090 [49]2 years ago

5 0

You got add all the numbers up and divide it by how many numbers there are to get the average.
9.4 +9.7 + 9.9 + 9.8 = 38.8 divided by 4 =9.7 is Joey's average.
9.5 +9.2 +9.7 +9.6 =38 divided by 4 = 9.5 is Carlos' average.
Joey has more average by 0.2.

postnew [5] · Answer 2 · 2022-06-03T21:01:02+03:00

postnew [5]2 years ago

4 0

Joey has more by 0.2 Hope this helps =)