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1 year ago

Find the area round to two decimal places as needed

1 answer:

3 0

To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:

$A=\frac{b\cdot h}{2}$

The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:

$\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}$

The area of the triangle is 28 square miles.

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An 80-foot rope is attached to a boat

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An 80-foot rope is attached to a boat

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3 years ago

Which represents a quadratic function?

Lisa [10]

Answer:

f(x)=start fraction 4 over x squared End fraction minus start fraction 2 over x end fraction +1

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3 years ago

Read 2 more answers

Help pls. I will give brainliest

Iteru [2.4K]

Answer: AC is congruent to PR.

Step-by-step explanation:

Letter A takes the corresponding position as letter P, and letter C takes the corresponding position as letter R in the given congruence statement.

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2 years ago

-4(2x-3)>-28 please i need this result

Len [333]

-4 (2x - 3) > -28

Divide by -4 on both sides. Since we're dividing by a negative, we need to switch the sign.

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3 0

3 years ago

A ball is thrown straight out at 80 feet per second from an upstairs window that's 15 feet off the ground. Find the ball's horiz

Alex73 [517]

Answer:

Step-by-step explanation:

In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:

a = -32 ft/s/s

v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)

Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)

t = ?? sec.

The equation we will use is the one for displacement:

Δx = $v_0t+\frac{1}{2}at^2$ and filling in:

$-15=(0)t+\frac{1}{2}(-32)t^2$ which simplifies down to

$-15=-16t^2$ so

$t=\sqrt{\frac{-15}{-16} }$ so

t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)

Now we use that time in the x-dimension. Here's what we know in that dimension specifically:

a = 0 (acceleration in this dimension is always 0)

v₀ = 80 ft/sec

t = .968 sec

Δx = ?? feet

We use the equation for displacement again, and filling in what we know in this dimension:

Δx = $(80)(.968) +(0)(.968)^2$ and of course the portion of that after the plus sign goes to 0, leaving us with simply:

Δx = (80)(.968)

Δx = 77.46 feet

5 0

3 years ago