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wariber [46]
1 year ago
11

Find the area round to two decimal places as needed

Mathematics
1 answer:
Mademuasel [1]1 year ago
3 0

To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:

A=\frac{b\cdot h}{2}

The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:

\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}

The area of the triangle is 28 square miles.

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• Subtract first: 333 - 112 = 221

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• Equation: (333 - 112) ÷ 4

Barb deposited $55.25 each month. 

Hope this helps! :D

~PutarPotato
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Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

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Step-by-step explanation:

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Step-by-step explanation:

DIFFERENTIATE W.R.T. X

3

EVALUATE

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